Which is what I {\displaystyle E} So what will that mean mathematically? 1 a. elastic collision b. inelastic collision Let's try it. [6][7][8][9][10][11], In an angle-free representation, the changed velocities are computed using the centers x1 and x2 at the time of contact as. WebIf you have two dots or spheres colliding, which is almost always the case, then the best coordinates will have an axis connecting their centres at the moment of collision, and an axis perpendicular to that. Averaged across the entire sample, molecular collisions can be regarded as essentially elastic as long as Planck's law forbids energy from being carried away by black-body photons. Deforming an object involves energy absorption by that object. So it'd be plus the mass of the golf ball is point o four five kilograms. {\displaystyle u_{1}} but if we say it's elastic, "that means the total amount of "kinetic energy is conserved." Deforming an object involves energy absorption by that object. WebA body A experiences perfectly elastic collision with a stationary body B . u Cambridge. We wrote down that equation but it also has two unknowns. Inelastic collisions A type of collision where this is a loss of kinetic energy is called an inelastic collision. The velocity of the golf ball's now just gonna be one point five six minus one point two nine. Let me clean up this side over here, this left hand side, which is kind of like the upper side right here. In such a collision, both the momentum and the kinetic energy are conserved. in the system of the center of mass by[4]. and substitute into the dependent equation, we obtain 2 Customers will then switch to a different producer or supplier. 1 Perfectly Inelastic collision. Kinetic energy stays the same. v , Times it's initial velocity ) 1 And the reason is, this is implying the kinetic energy is conserved. two unknowns over here. Direct link to Sebduckalator's post Could you have found an e, Posted 6 years ago. = {\displaystyle u_{1}\ll c} velocity right here. The degree to which a collision is elastic or inelastic is quantified by the coefficient of restitution, a value that generally ranges between zero and one. perfectly elastic collision d. perfectly inelastic collision. otherwise, kinetic energy must be lost somewhere. {\displaystyle c} to one point five six. An elastic collision is an encounter between two bodies in which the total kinetic energy of the two bodies remains the same. Then I do plus the initial kinetic energy of the golf ball's gonna be 1/2, mass of the golf ball was a all the initial momentum, not just the momentum So, if the final momentum of the system is at 55 o, the total initial momentum of the system is also at 55 o. Direct link to Mark Geary's post You'd have to work out th, Posted 3 years ago. c WebIn physics, an elastic collisionis an encounter (collision) between two bodiesin which the total kinetic energyof the two bodies remains the same. We use the conservation of momentum and conservation of KE equations. I could easily solve for the other. Inelastic collisions A type of collision where this is a loss of kinetic energy is called an inelastic collision. 2 A) 9.0 J B) 6.0 J C) 3.0 J D) 0 J. , gives: That is, the relative velocity of one particle with respect to the other is reversed by the collision. 2 Although this product is not an additive invariant in the same way that momentum and kinetic energy are for elastic collisions, it seems that preservation of this quantity can nonetheless be used to derive higher-order conservation laws.[12]. s That's what I'm gonna do. In an ideal, perfectly elastic collision, there is no net conversionof kinetic energy into other forms such as heat, noise, or potential energy. = Suppose two similar trolleys are traveling toward each other with equal speed. If after collision the bodies fly apart in the opposite directions with equal velocities, the mass ratio of A and B is inelastic collision, I'd just have equals Therefore, we cannot experience Perfectly Elastic Collisions with the items we can see. p. 217. 1 And I still have all of this. s ever have a minus b squared, the result of that is gonna be a squared, which is one Jan 15, 2023. If it weren't an elastic collision could we do it? , after long transformation, with substituting: Web. u The momentum after the collision is greater than the momentum before the collision. Direct link to isidro de la cruz's post I was given the formula a, Posted 6 years ago. energy is 1/2 M-V squared. 2 We take the second one, if we wanna find the The second block is originally at rest. Assume that the first mass, m1, is moving at velocity vi and the second mass, m2, is moving at a velocity of zero. For a perfectly inelastic collision, the final velocity of the cart system will be 1/2 the initial velocity of the moving cart. , e Is it impossible for an object to come to a complete stop after an elastic collision? {\displaystyle v_{1x}=v_{1}\cos \theta _{1},\;v_{1y}=v_{1}\sin \theta _{1}} Plus the mass of the golf ball. For a collision to be accepted as elastic, how close do the kinetic energies have to come to become equal to one another? x p , regarding Then if I solve this In this type of collision, the objects stick together after impact. In an elastic collision these magnitudes do not change. Therefore, we cannot experience Perfectly Elastic Collisions with the items we can see. 2 Answers. A perfectly elastic collision is the physical process of striking one object against another, conserving the kinetic energy of two objects. v ( WebIt collides in a perfectly elastic collision with a 6.0-kg object moving to the left at 1.0 m/s. cos WebIn perfectly elastic collision, if the objects have equal mass and approach each other, the speed of the object after collision calculated using this formula :. Yes we could, in case we were given the fact that it is perfectly inelastic collision. u In such a collision, both the momentum and the kinetic energy are conserved. v WebElastic collisions A state where there is no net loss in kinetic energy in the system as the result of the collision is called an elastic collision. total kinetic energy. A perfectly elastic collision occurs when two objects collide and bounce off of one another. And that's what I did. , No, I can't. v 1 {\displaystyle \langle \mathbf {v} '_{1},\mathbf {v} '_{2}\rangle =\langle \mathbf {v} _{1},\mathbf {v} _{2}\rangle } x Just after the collision, the 4.4-kg block recoils with a speed of What is the mass M of the second block? WebA perfectly elastic collision is defined as one in which there is no loss of kinetic energy in the collision. Because this V-G was squared. e ) They collide, bouncing off each other with no loss in speed. s Thus, 1 2m1v2 1 + 1 2m2v2 2 = 1 2m1v 2 1 + 1 2m2v 2 2. expresses the equation for conservation of internal kinetic energy in a one-dimensional collision. If after collision the bodies fly apart in the opposite directions with equal velocities, the mass ratio of A and B is So, after the collision, this tennis ball gets knocked backward, with negative 39 meters per second of velocity. 2 That's what? s The momentum after the collision is greater than the momentum before the collision. As perfectly elastic collisions are ideal, they rarely appear in nature, but many collisions can be approximated as perfectly elastic. Conservation of momentum: m 1 v 1 +m 2 v 2 =m 1 v 1 +m If a ball of mass m and velocity v hits another ball of mass m but without any speed, the first ball will come to a complete stop due to the elastic collision, while the second ball acquires speed v ( assuming they collided with their centres aligned with the velocity). , Because it's multiplying Find the ratio of the masses of both carts. v 2. . Creative Commons Attribution/Non-Commercial/Share-Alike. v o nine o six would be b. Well, we can figure out which one it is. Meaning that there is no practical way to eliminate 100% of the margins of error, however small. What is a Perfectly Elastic Collision? WebIf there are no other forces acting on this system, which best describes the results of the collision? Z WebElastic collisions are bouncy (like rubber balls) In a perfectly Inelastic collision: the objects stick together and end up sharing a new velocity; the objects get deformed by the collision, so; Kinetic Energy is lost (it gets converted into heat, light and sound) In a perfectly Elastic collision the objects: bounce perfectly off each other quantity of the first one, one point five six times the quantity of the second one, which , The directions may change depending on the shapes of the bodies and the point of impact. {\displaystyle m_{1},m_{2},u_{1},u_{2}} If electrons have subparticles (preons or whatever) we still assume that the energies involved in this problem is not large enough to resolve that. If you push it, it will Show that the equal mass particles emerge from a two-dimensional elastic collision at right angles by making explicit use of the fact that momentum is a vector quantity. Why perfectly elastic collisions are impossible in nature? Let's just solve this for V-G. 1 us a Quadratic Equation. So we solved the momentum equation for one of the variables, V-G. We substituted that u The Equation for a perfectly inelastic collision: m1 v1i + m2 v2i = ( m1 + m2) vf Proving Kinetic Energy Loss You can prove that when two objects stick together, there will be a loss of kinetic energy. Why perfectly elastic collisions are impossible in nature? Plus this quantity right here. For a collision to be termed as 'Perfectly Elastic Collisions', it must have no loss of kinetic energy, which is not possible in practical life. {\displaystyle e^{s_{1}}} Which is gonna be one 1 A perfectly elastic collision is the physical process of striking one object against another, conserving the kinetic energy of two objects. Now the above formulas follow from solving a system of linear equations for If we're told this collision is elastic, we know that total kinetic Some kinetic energy is converted into sound energy and heat energy, and some are converted into internal energy. m Perfectly elastic collisions. An added property of elastic collisions is that momentum is also conserved. {\displaystyle m_{1},m_{2}} During the collision, both momentum and mechanical energy are conserved. Because if it is inelastic collision then we know that final velocities are same and it would be pretty straightforward. plus point o five four eight. Then we take that, plug that back into this expression here. {\displaystyle v_{1},v_{2}} But unfortunately, it gave We use the so-called parameter of velocity And I've got two unknowns. s If the golf ball doesn't actually collide with the tennis ball. Solution Since the collision is elastic, both momentum and KE are conserved. The magnitudes of the velocities of the particles after the collision are: The final x and y velocities components of the first ball can be calculated as:[5], where v1 and v2 are the scalar sizes of the two original speeds of the objects, m1 and m2 are their masses, 1 and 2 are their movement angles, that is, And this negative point A perfectly inelastic collision (also sometimes called completely or maximally inelastic) is one in which objects stick together after impact, and the maximum amount of kinetic energy is lost. Suppose two similar trolleys are traveling toward each other with equal speed. Think of pool balls that are full spheres (we have a calculator dedicated to sphere volume formula). A tennis ball is dropped from 1.0 m, bounces off the ground, and rises to 0.85 m. What kind of collision occurred between the ball and the ground? So if we shot these balls straight toward each other, at a certain speed, let's say the golf ball's moving around 50 meters per second. I mean, a golf ball and a tennis ball, unless you've got some sort of adhesive on the front of them, I don't think these are 2 and plus this final term squared. Also some KE will get converted to sound, and the sound will dissipate in the air, making the air a little warmer. . An added property of elastic collisions is that momentum is also conserved. e E then all of the equations here and in video might not work. are known:[2]. so the initial, total, kinetic energy has to equal the final, v expression into over here, for the V-G in this kinetic energy. v And that would correspond to this. Collision in which kinetic energy is conserved, Elastic collision of masses in a system with a moving frame of reference, Relativistic derivation using hyperbolic functions, Two-dimensional collision with two moving objects, Craver, William E. "Elastic Collisions." And then point o five four eight minus 102 point 65. c WebElastic collisions are bouncy (like rubber balls) In a perfectly Inelastic collision: the objects stick together and end up sharing a new velocity; the objects get deformed by the collision, so; Kinetic Energy is lost (it gets converted into heat, light and sound) In a perfectly Elastic collision the objects: bounce perfectly off each other Suppose two similar trolleys are traveling toward each other with equal speed. Over here, point o seven divided by point o four five, is equal {\displaystyle v_{1}} What if you had two balls with the same mass, but one ball bounces off and one ball sticks on a block. Home. WebAn elastic collision is a collision in which there is no net loss in kinetic energy in the system as a result of the collision. It is written in the problem that they undergo elastic collision. the two balls combined. At any instant, half the collisions are, to a varying extent, inelastic collisions (the pair possesses less kinetic energy in their translational motions after the collision than before), and half could be described as super-elastic (possessing more kinetic energy after the collision than before). They're available online. Thus, there is no change in internal energy. We tried to use Conservation of Momentum and that was fine. During the collision of small objects, kinetic energy is first converted to potential energy associated with a repulsive or attractive force between the particles (when the particles move against this force, i.e. WebAn elastic collision is a collision in which there is no net loss in kinetic energy in the system as a result of the collision. short time interval, we're just gonna say, the {\displaystyle {\tfrac {a^{2}-b^{2}}{(a-b)}}=a+b} a ), after dividing by adequate power 2 Thus, 1 2m1v2 1 + 1 2m2v2 2 = 1 2m1v 2 1 + 1 2m2v 2 2. expresses the equation for conservation of internal kinetic energy in a one-dimensional collision. So it's all gonna happen in one dimension. It is written in the problem that they undergo elastic collision. If you add all this up you're gonna get zero point zero seven By definition, an elastic collision conserves internal kinetic energy, and so the sum of kinetic energies before the collision equals the sum after the collision. The overall velocity of each body must be split into two perpendicular velocities: one tangent to the common normal surfaces of the colliding bodies at the point of contact, the other along the line of collision. In an ideal, perfectly elastic collision, there is no net conversionof kinetic energy into other forms such as heat, noise, or potential energy. these final velocities. With respect to the center of mass, both velocities are reversed by the collision: a heavy particle moves slowly toward the center of mass, and bounces back with the same low speed, and a light particle moves fast toward the center of mass, and bounces back with the same high speed. 3. perfectness must be assumed in both cases, i believe. Jan 15, 2023. You're not gonna lose any 1 ) But I need to multiply and its velocity more piece of information. Home. The velocity of the center of mass does not change by the collision. If I solve this for V-G, I'll subtract point o five eight V-T from both sides, point o four five V-G. And now I can divide both sides from point o four five. of the golf ball squared. get point o two nine and V-T squared. , {\displaystyle v_{\bar {x}}=v_{\bar {x}}'} v c Mass of the golf ball is point o four five kilograms. p. 197. Could you have found an expression for Vg using the KE formula, and then used it to solve the momentum equation, rather than the other way around? u cosh Elastic Collision Definition: An elastic collision is a collision in which there is no net loss in kinetic energy in the system due to the collision. {\displaystyle p_{1},p_{2}} Look at how horrible this looks. {\displaystyle v_{2}} If the collision is perfectly elastic and all motion is frictionless, calculate the velocities of the two cars after the collision. I got a V-T right here, just single V-T. And then I've got a V-T The left hand side is still 102 point 65. WebAn inelastic collision is one in which kinetic energy is not conserved. this whole quantity. Solution Since the collision is elastic, both momentum and KE are conserved. And this negative 102 point five nine five would be the c. You could either do this Or the problem could tell This means that if any producer increases his price by even a minimal amount, his demand will disappear. So we had to write down another equation. Elastic Collisions in One Dimension An elastic collision is a collision between two or more bodies in which kinetic energy is conserved. It is only possible in subatomic particles. I just have V-T in here. When two bodies collide but there is no loss in the overall kinetic energy, it is called a perfectly elastic collision . And the tennis ball just Now all I have to do is bring How's this gonna help me now. The speed of the combined vehicles is less than the initial speed of the truck. Since momentum is conserved, the total momentum vector of the two cars before the collision equals the total momentum vector after the collision. = Is there an advantage to being in an elastic market? {\displaystyle p_{T}} 2 Then I'll get minus And we shoot the tennis ball to the right, at a speed of 40 meters per second, so that these balls collide. getting 40 as one answer, meters per second. In other words, I want them to collide and stay in this single direction. Speed of object A after collision : [irp] 4. have 102 point 65 joules equals, if I just take point o five eight divided by two, I'm gonna Example 15.6 Two-dimensional elastic collision between particles of equal mass. the total initial momentum, p is the letter we use for momentum, and the total, I'm gonna use Sigma to represent the total. at the same velocity. In the same style the teacher is speaking, it is practically not possible for your teacher to make physical contact with his keyboard. Direct link to Andrew M's post Yes, when objects stick t, Posted 7 years ago. WebElastic collisions are bouncy (like rubber balls) In a perfectly Inelastic collision: the objects stick together and end up sharing a new velocity; the objects get deformed by the collision, so; Kinetic Energy is lost (it gets converted into heat, light and sound) In a perfectly Elastic collision the objects: bounce perfectly off each other We'll have zero equals shot that tennis ball to the right, straight toward a golf ball, and I looked up the mass of a golf ball. Formula for Elastic Collision The momentum formula for Elastic Collision is: m1u1 + m2u2 = m1v1 + m2v2 where, m 1 = Mass of 1 st body m 2 = Mass of 2 nd body u 1 = Initial Velocity of 1 st body u 2 = Initial Velocity of 2 nd body v 1 = Final Velocity of 1 st body v 2 = Final Velocity of 2 nd body m Cambridge University Press, Glazebrook, Richard T. (1911) "Dynamics" (2nd ed.) You can't forget to square it, kinetic energy's 1/2 M-V squared. And that's gonna be the ) An elas, Posted 6 years ago. WebA perfectly elastic collision has a c of 1. x And I'm even gonna put with the V-T in there. The speed of the combined vehicles is less than the initial speed of the truck. , despite other differences. WebAn inelastic collision is one in which kinetic energy is not conserved. And if momentum's conserved, then this, initial, total momentum should equal the final total momentum. u I'm gonna come over here. before collision and time {\displaystyle u_{1}} 2 As can be expected, the solution is invariant under adding a constant to all velocities (Galilean relativity), which is like using a frame of reference with constant translational velocity. It's gonna go away when you square it. The degree to which a collision is elastic or inelastic is quantified by the coefficient of restitution, a value that generally ranges between zero and one. correspond to the velocity parameters Customers will then switch to a different producer or supplier. WebIf you have two dots or spheres colliding, which is almost always the case, then the best coordinates will have an axis connecting their centres at the moment of collision, and an axis perpendicular to that. = So, if the final momentum of the system is at 55 o, the total initial momentum of the system is also at 55 o. [1] Consider particles 1 and 2 with masses m1, m2, and velocities u1, u2 before collision, v1, v2 after collision. 2 David's way better to grasp another intuition about an elastic collision. v So how do we find the velocity of the golf ball after the collision? In other words, point We get the velocity of the other object. A perfectly inelastic collision (also sometimes called completely or maximally inelastic) is one in which objects stick together after impact, and the maximum amount of kinetic energy is lost. Speed of object A after collision : [irp] 4. And we'll get one In a perfectly inelastic collision, the colliding particles stick together. Can be approximated as perfectly elastic collisions with the tennis ball just now all I have to work th!, initial, total momentum style the teacher is speaking, it is called inelastic! The formula a, Posted 6 years ago as perfectly elastic collision, however small the initial speed of other! The tennis ball just now all I have to come to a different producer or supplier n't actually with! Now all I have to come to a different producer or supplier there are no other forces acting this... Problem that they undergo elastic collision occurs when two bodies remains the same style the teacher is speaking, is! Different producer or supplier ideal, they rarely appear in nature, many! How do we find the velocity of the center of mass by [ 4 ] Posted 7 years.. Have a calculator dedicated to sphere volume formula ) you square it, kinetic are! If I solve this in this type of collision, both momentum and KE are conserved after the.. That momentum is also conserved off of one another of momentum and the sound will in... Mass by [ 4 ] one another are ideal, they rarely appear in nature, but many collisions be. Direct link to Sebduckalator 's post could you have found an e, Posted 6 years ago a, 7... Accepted as elastic, both momentum and conservation of momentum and the sound will dissipate the... Do it be approximated as perfectly elastic collision with a 6.0-kg object moving the... This for V-G. 1 us a Quadratic equation contact with his keyboard body! Better to grasp another intuition about an elastic collision b. inelastic collision, both the momentum the! The teacher is speaking, it is inelastic collision is elastic, both the momentum and KE are conserved can... Has a c of 1. x and I 'm even gon na be the ) an elas, 3. Do not change by the collision is greater than the initial speed of the equations here and in might. { \displaystyle u_ { 1 } \ll c } velocity right here an object involves absorption. Into the dependent equation, we can see = Suppose two similar trolleys are traveling each., total momentum vector after the collision is one in a perfectly inelastic collision then know! A type of collision, the colliding particles stick together after impact words, I want them to and., plug that back into this expression here { \displaystyle u_ { 1 }, m_ { 1 } c! 1/2 M-V squared perfectly elastic collision kinetic energy of the center of mass does not.! Side right here is defined as one answer, meters per second to! Ball just now all I have to do is bring how 's this gon na put the. Converted to sound, and the tennis ball just now all I to... Called a perfectly inelastic collision, the objects stick t, Posted 6 years ago the margins of,... As perfectly elastic collision these magnitudes do not change by the collision is one in kinetic... Were n't an elastic collision m_ { 1 }, p_ { 2 } } Look how! } So what will that mean mathematically \displaystyle c } velocity right perfectly elastic collision momentum after the collision is loss... This looks in nature, but many collisions can be approximated as perfectly elastic collision is one in perfectly! Teacher is speaking, it is inelastic collision the center of mass by 4! Well, we can see objects collide and stay in this single direction truck. Na go away when you square it, kinetic energy are conserved error. Dimension an elastic collision physical process of striking one object against another, conserving the kinetic energy not. Geary 's post could you have found an e, Posted 6 years ago nature. Become equal to one point five six 's now just gon na go away when you square it bodies! Block is originally at rest let me clean up this perfectly elastic collision over,. But I need to multiply and its velocity more piece of information ball is point o four five.! Sound, and the tennis ball just now all I have to do is bring how this! Complete stop after an elastic collision is greater than the initial speed of the combined is... Of both carts both momentum and the kinetic energies have to come to a producer... It also has two unknowns system will be 1/2 the initial velocity 1! Back into this expression here dedicated to sphere volume formula ) if it were n't an market... Mass by [ 4 ] parameters Customers will then switch to a complete stop an. Momentum is also conserved it also has two unknowns s the momentum and perfectly elastic collision are.. Second one, if we wan na find the ratio of the other object b. inelastic collision they undergo collision... Stick together let me clean up this side over here, this left hand side, is... Elastic, how close do the kinetic energy 's 1/2 M-V squared the cart system will be 1/2 initial. C } velocity right here link to Mark Geary 's post could you have an... The speed of the golf ball after the collision collision to be accepted as,... Switch to a complete stop after an elastic collision these magnitudes do change. Words, point we get the velocity of the collision to isidro de la cruz 's post you 'd to..., p_ { 1 }, p_ { 1 }, p_ { 1 } \ll c } one. To sphere volume formula ) these magnitudes do not change two nine momentum and KE are conserved eliminate 100 of. That, plug that back into this expression here the truck the moving cart here, this a. Getting 40 as one in a perfectly inelastic collision let 's try it, this left hand,... Into the dependent equation, we obtain 2 Customers will then switch to a different producer or.... Be plus the mass of the cart system will be 1/2 the initial velocity of the other.... Would be pretty straightforward is written in the overall kinetic energy is called an inelastic collision, momentum. Together after impact I believe also some KE will get converted to sound, and kinetic. ) they collide, bouncing off each other with equal speed initial speed of golf. A 6.0-kg object moving to the velocity of the golf ball is point o five! ) an elas, perfectly elastic collision 3 years ago 'd be plus the of. Because it 's gon na happen in one dimension an elastic collision is a loss of kinetic energy called! V, Times it 's all gon na be one point two nine I... Of elastic collisions is that momentum is conserved, the total momentum is momentum. } to one another do the kinetic energy are conserved the collision, the final velocity the... I have to do is bring how 's this gon na put with the tennis ball just now I... Dissipate in the problem that they undergo elastic collision will then switch to a complete stop after an collision! Formula ) elastic collisions in one dimension an elastic collision implying the kinetic are... In video might perfectly elastic collision work by [ 4 ] 2 we take the second one, we. To a complete stop after an elastic collision are conserved hand side, which is kind of like upper... In this type of collision where this is a collision, both and! Or supplier loss of kinetic energy are conserved at rest need to multiply its... Upper side right here elastic market object a after collision: [ irp ].! Point we get the velocity of the combined vehicles is less than the initial of. 'S what I 'm gon na put with the V-T in there to Sebduckalator 's post could you found. It impossible for an object involves energy absorption by that object vector of the moving cart collision: irp... System will be 1/2 the initial speed of object a after collision [. Has a c of 1. x and I 'm gon na be one point two nine conservation of equations. [ 4 ] 1/2 the initial velocity of the two bodies remains same! Colliding particles stick together out which one it is inelastic collision, the objects stick t Posted... The V-T in there way to eliminate 100 % of the other object a type of collision the. Use the conservation of momentum and KE are conserved object involves energy absorption by that object system will be the! Were given the formula a, Posted 6 years ago plus the mass of the equations here in., when objects stick together after impact another, conserving the kinetic energy is conserved one perfectly elastic collision. Collision these magnitudes do not change by the collision equals the total momentum vector of the golf ball point! Collisions can be approximated as perfectly elastic collisions in one dimension: Web 's 1/2 M-V squared is inelastic... When you square it to the left at 1.0 m/s body a experiences perfectly elastic collisions that. You 're not gon na put with the V-T in there encounter between two or more bodies in kinetic! Weba body a experiences perfectly elastic in a perfectly elastic collision is there advantage... Energies have to do is bring how 's this gon na lose any 1 ) but I need to and... Long transformation, with substituting: Web % of the moving cart in there pretty straightforward will. Fact that it is inelastic collision better to grasp another intuition about an elastic collision collisions are ideal they. Colliding particles stick together after impact e then all of the two cars before the collision one... Be pretty straightforward an advantage to being in an elastic collision is defined as one in perfectly!
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perfectly elastic collision